### Chap 6 Error Analysis Homework 2 Ex 6.2 Q1(j)

Go through the working and attempt to identify where the error is.

#### 14 comments:

1. Should be -8x not 8x.

2. On Line 3, the 8x should be -8x.

3. he should not change the -8x as it did not 'move' to the other side

4. This comment has been removed by the author.

5. 2-8x should be -8x and not 8x.

6. Line 4. It should be -8x and not 8x

7. There is a mistake at Line 4. It should be -8x = 43-9x not 8x = 43 - 9x.

8. from line 3 to 4 the minus sign for -8x disappears

9. There is a mistake on line 4 . It should be -8 instead of 8 as he did not 'move ' the 8 so it should remain the same

10. The steps are too quick and rushed until it is hard to see what is going on. The main mistake was when 2-8x, and 2 is carried over but the minus sign next to the 8x was not, but somehow it disappeared.

-Alex

11. On line 4, 8x should be negative 8x.

12. The problem starts from line 4. It should be -8x = 43 - 9x . Therefore, line 5 should be x = 43 .

13. The charge of the number can be determined by looking at the operation at the left of the number. As the operation before 8 is a minus, It is minus 8 not 8