Chap 6 Error Analysis Homework 2 Ex 6.2 Q1(j)

Go through the working and attempt to identify where the error is.

14 comments:

  1. he should not change the -8x as it did not 'move' to the other side

    ReplyDelete
  2. This comment has been removed by the author.

    ReplyDelete
  3. 2-8x should be -8x and not 8x.

    ReplyDelete
  4. Line 4. It should be -8x and not 8x

    ReplyDelete
  5. There is a mistake at Line 4. It should be -8x = 43-9x not 8x = 43 - 9x.

    ReplyDelete
  6. from line 3 to 4 the minus sign for -8x disappears

    ReplyDelete
  7. There is a mistake on line 4 . It should be -8 instead of 8 as he did not 'move ' the 8 so it should remain the same

    ReplyDelete
  8. The steps are too quick and rushed until it is hard to see what is going on. The main mistake was when 2-8x, and 2 is carried over but the minus sign next to the 8x was not, but somehow it disappeared.

    -Alex

    ReplyDelete
  9. On line 4, 8x should be negative 8x.

    ReplyDelete
  10. The problem starts from line 4. It should be -8x = 43 - 9x . Therefore, line 5 should be x = 43 .

    ReplyDelete
  11. The charge of the number can be determined by looking at the operation at the left of the number. As the operation before 8 is a minus, It is minus 8 not 8

    ReplyDelete